My Solution to "100 H.S.M.O. Geometry Problems" P18

2026.03.04

My Solution to "100 H.S.M.O. Geometry Problems" P18

Preface

If you are unfamiliar with the common properties of complete quadrilaterals, you can first check it out on AOPS。


The Problem

Problem 18: As shown in the figure, A, B, C, D are four points arranged in order on ⊙O. Lines BA and CD intersect at point E; lines AC and BD intersect at point F. G and H are the midpoints of AC and BD respectively. Line GH intersects AB and CD at M and N. Construct the circumcircle ⊙P of △EMN, and construct ⊙Q with OF as the diameter. Prove: ⊙P and ⊙Q are tangent to each other.





By observation, points H and G lie on ⊙(OF), which can be proven by the Perpendicular Chord Theorem. When a problem involving tangent circles features a complete quadrilateral, the tangency point is often its Miquel point.





Introducing the Miquel point M of AEDCFB, we observe that M is the point of tangency. From the properties of complete quadrilaterals with concyclic feet, we can derive OM ⊥ EM (radical axis of constant difference, via inversion power of the blue circle), thus M lies on ⊙(OF).





Returning to the original problem, let T be the Miquel point of AEDCFB. Then HFGT are concyclic and AFTB are concyclic. Thus, T is also the Miquel point of AFGHMB, which makes MHTB concyclic. Similarly, NGTC are concyclic. Furthermore, we know that ∠MTH = ∠MBH = ∠GCN = ∠GTN. The proof follows from the properties of equal angles in tangent circles (refer to P17 for the detailed proof).


Summary

This is a very friendly problem; if you have just started learning about complete quadrilaterals, it serves as a good exercise. However, it might be a bit light for intensive competition training.

translated by me from my original post on bilibili
2026/3/4